2y^2-16y+64=32

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Solution for 2y^2-16y+64=32 equation: 



2y^2-16y+64=32

We move all terms to the left:

2y^2-16y+64-(32)=0

We add all the numbers together, and all the variables

2y^2-16y+32=0

a = 2; b = -16; c = +32;
Δ = b2-4ac
Δ = -162-4·2·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{16}{4}=4$

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